a substance has a specific heat of 0.870 j/g°c. it requires 2,000.0 joules to increase the temperature of…
a substance has a specific heat of 0.870 j/g°c. it requires 2,000.0 joules to increase the temperature of 10.0 grams of the substance from its original temperature to its final temperature. by how many degrees did the substance increase? 87.0°c 174°c 230°c 1,740°c
Answer
Explanation:
Step1: Recall the heat - transfer formula
The heat - transfer formula is $Q = mc\Delta T$, where $Q$ is the heat energy transferred, $m$ is the mass of the substance, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature. We need to solve for $\Delta T$.
Step2: Rearrange the formula for $\Delta T$
From $Q = mc\Delta T$, we can solve for $\Delta T$ as $\Delta T=\frac{Q}{mc}$.
Step3: Substitute the given values
We are given that $Q = 2000.0\ J$, $m = 10.0\ g$, and $c=0.870\ J/g^{\circ}C$. Substituting these values into the formula $\Delta T=\frac{Q}{mc}$, we get $\Delta T=\frac{2000.0\ J}{10.0\ g\times0.870\ J/g^{\circ}C}$.
Step4: Calculate the result
$\Delta T=\frac{2000.0}{10.0\times0.870}=\frac{2000.0}{8.7}\approx230^{\circ}C$.
Answer:
$230^{\circ}C$