a suitcase initially at rest, is pulled with a force of 34.6 n at a 58.6° angle over a distance of 10.9 m. a…

Answer:

76.4

Explanation:

Step1: Calculate work done by pulling - force

The formula for work is $W = Fd\cos\theta$. Here, $F = 34.6$ N, $d = 10.9$ m, and $\theta=58.6^{\circ}$. So, $W_1=Fd\cos\theta=34.6\times10.9\times\cos(58.6^{\circ})$. $W_1 = 34.6\times10.9\times0.521 = 34.6\times5.6789=196.4$.

Step2: Calculate work done by friction - force

The friction force $F_f = 17.8$ N and the displacement $d = 10.9$ m. The angle between the friction force and the displacement is $180^{\circ}$, and $\cos(180^{\circ})=- 1$. So, $W_f=F_f d\cos(180^{\circ})=-17.8\times10.9=-194$.

Step3: Calculate total work

Using the formula $W = W_1+W_f$, we substitute the values of $W_1$ and $W_f$. $W=196.4+( - 194)=76.4$ J.