suppose a 4.0 kg mass of water gained heat and increased in temperature from 10°c to 15°c. the specific heat…

suppose a 4.0 kg mass of water gained heat and increased in temperature from 10°c to 15°c. the specific heat capacity of water is 4.186 kj/kg°c. how much heat was gained by the water?\n9.6 kj\n20 kj\n56 kj\n84 kj
Answer
Explanation:
Step1: Identify the formula
The formula for heat transfer is $Q = mc\Delta T$, where $Q$ is the heat transferred, $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature.
Step2: Calculate the change in temperature
$\Delta T=T_2 - T_1=15^{\circ}C - 10^{\circ}C = 5^{\circ}C$
Step3: Substitute the values into the formula
$m = 4.0\ kg$, $c = 4.186\ kJ/kg^{\circ}C$, $\Delta T = 5^{\circ}C$ $Q=mc\Delta T=(4.0\ kg)\times(4.186\ kJ/kg^{\circ}C)\times(5^{\circ}C)$ $Q = 83.72\ kJ\approx84\ kJ$
Answer:
D. 84 kJ