the table shows the approximate height of a projectile x seconds after being fired into the air. which…

the table shows the approximate height of a projectile x seconds after being fired into the air. which equation models the height, y, x seconds after firing? projectile motion time (seconds) height (meters) x y 0 0 1 40 2 60 3 60 4 40 5 0 y = -10(x)(x - 5) y = 10(x)(x - 5) y = -10(x - 5) y = 10(x - 5)

the table shows the approximate height of a projectile x seconds after being fired into the air. which equation models the height, y, x seconds after firing? projectile motion time (seconds) height (meters) x y 0 0 1 40 2 60 3 60 4 40 5 0 y = -10(x)(x - 5) y = 10(x)(x - 5) y = -10(x - 5) y = 10(x - 5)

Answer

Explanation:

Step1: Test x = 0

Substitute x = 0 into each equation. For $y=-10(x)(x - 5)$, when $x = 0$, $y=-10\times0\times(0 - 5)=0$. For $y = 10(x)(x - 5)$, when $x = 0$, $y=10\times0\times(0 - 5)=0$. For $y=-10(x - 5)$, when $x = 0$, $y=-10\times(0 - 5)=50$. For $y = 10(x - 5)$, when $x = 0$, $y=10\times(0 - 5)=- 50$. So we can eliminate the last two - equations.

Step2: Test x = 1

Substitute x = 1 into $y=-10(x)(x - 5)$ and $y = 10(x)(x - 5)$. For $y=-10(x)(x - 5)$, when $x = 1$, $y=-10\times1\times(1 - 5)=-10\times(-4)=40$. For $y = 10(x)(x - 5)$, when $x = 1$, $y=10\times1\times(1 - 5)=10\times(-4)=-40$.

Answer:

$y=-10(x)(x - 5)$