$-4\tan(-180^{circ})^{2}-4(sin90^{circ})^{7}$

Explanation:

Step1: Evaluate $\tan(-180^{\circ})$

Since $\tan(-\alpha)=-\tan\alpha$ and $\tan180^{\circ} = 0$, then $\tan(-180^{\circ})=0$. So $[\tan(-180^{\circ})]^2 = 0^2=0$.

Step2: Evaluate $\sin90^{\circ}$

We know that $\sin90^{\circ}=1$, so $(\sin90^{\circ})^7=1^7 = 1$.

Step3: Calculate the whole - expression

Substitute the above results into the original expression: $-4\times0-4\times1=-4$.

Answer:

$-4$