what is the temperature of 0.80 mol of a gas stored in a 275 ml cylinder at 175 kpa? use $pv = nrt$ and $r =…

what is the temperature of 0.80 mol of a gas stored in a 275 ml cylinder at 175 kpa? use $pv = nrt$ and $r = 8.314\frac{lcdot kpa}{molcdot k}$. 4.6 k 7.2 k 61 k 96 k

what is the temperature of 0.80 mol of a gas stored in a 275 ml cylinder at 175 kpa? use $pv = nrt$ and $r = 8.314\frac{lcdot kpa}{molcdot k}$. 4.6 k 7.2 k 61 k 96 k

Answer

Explanation:

Step1: Convert volume to liters

$V = 275\ mL=275\times10^{- 3}\ L = 0.275\ L$

Step2: Rearrange the ideal - gas law for temperature

From $PV = nRT$, we can solve for $T$: $T=\frac{PV}{nR}$

Step3: Substitute the given values

$P = 175\ kPa$, $n = 0.80\ mol$, $V=0.275\ L$, $R = 8.314\frac{L\cdot kPa}{mol\cdot K}$ $T=\frac{175\ kPa\times0.275\ L}{0.80\ mol\times8.314\frac{L\cdot kPa}{mol\cdot K}}$ $T=\frac{47.875}{6.6512}\ K\approx7.2\ K$

Answer:

B. 7.2 K