a tennis ball is dropped from a certain height. its height in feet is given by $h = -16t^{2}+17$ where $t$…
a tennis ball is dropped from a certain height. its height in feet is given by $h = -16t^{2}+17$ where $t$ represents the time in seconds after launch. what is the balls initial height?
Answer
Explanation:
Step1: Identify initial time
Initial time means $t = 0$.
Step2: Substitute $t = 0$ into height - formula
Substitute $t=0$ into $h=-16t^{2}+17$. So $h=-16\times(0)^{2}+17$.
Step3: Calculate the height
Since $-16\times(0)^{2}=0$, then $h = 17$.
Answer:
17