test information\ndescription from the list of choice, select the one best option.\ninstructions from the…

test information\ndescription from the list of choice, select the one best option.\ninstructions from the list of choice, select the one best option.\nmultiple attempts not allowed. this test can only be taken once.\nforce completion this test can be saved and resumed later.\nyour answers are saved automatically.\nquestion completion status:\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26\nmoving to another question will save this response.\nquestion 13 of 26\nquestion 13 5 points save answer\nthe minimum takeoff speed for a certain airplane is 75 m/s. what minimum acceleration is required if the plane must leave a runway of length 1050 m? assume the plane starts from rest at one end of the runway.\n2.7 m/s²\n4.5 m/s²\n6.0 m/s²\n1.5 m/s²\n3.0 m/s²

test information\ndescription from the list of choice, select the one best option.\ninstructions from the list of choice, select the one best option.\nmultiple attempts not allowed. this test can only be taken once.\nforce completion this test can be saved and resumed later.\nyour answers are saved automatically.\nquestion completion status:\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26\nmoving to another question will save this response.\nquestion 13 of 26\nquestion 13 5 points save answer\nthe minimum takeoff speed for a certain airplane is 75 m/s. what minimum acceleration is required if the plane must leave a runway of length 1050 m? assume the plane starts from rest at one end of the runway.\n2.7 m/s²\n4.5 m/s²\n6.0 m/s²\n1.5 m/s²\n3.0 m/s²

Answer

Explanation:

Step1: Identify the kinematic - equation

We use the equation $v^{2}=v_{0}^{2}+2ax$, where $v$ is the final velocity, $v_{0}$ is the initial velocity, $a$ is the acceleration, and $x$ is the displacement.

Step2: Substitute the given values

Given $v = 75\ m/s$, $v_{0}=0\ m/s$ (starts from rest), and $x = 1050\ m$. Substituting into the equation $v^{2}=v_{0}^{2}+2ax$, we get $(75)^{2}=0^{2}+2a\times1050$.

Step3: Solve for acceleration $a$

First, expand the equation: $5625 = 2100a$. Then, solve for $a$: $a=\frac{5625}{2100}\approx2.7\ m/s^{2}$.

Answer:

$2.7\ m/s^{2}$