think about it!\n1. which task and distance resulted in the fastest speed?\ntask = speed walking distance =…

think about it!\n1. which task and distance resulted in the fastest speed?\ntask = speed walking distance = 5m speed = 1.64\n2. which task and distance resulted in the slowest speed?\ntask = walking back distance = 10m speed = 0.99\n3. how far could you speed walk in 10 minutes based on your speed for the 10 - meter trial? show your work!\n4. how long would it take you to hop 30 meters based on your speed for the 5 - meter trial? show your work!\nhow far could you travel walking backwards in 15 minutes based on your results for the 5 - meter trial? show your work!\nhow long would it take you to walk (regular rate) 1 kilometer (or 1,000 m) based on your speed? show your work!\nare the results accurate? why or why not?

think about it!\n1. which task and distance resulted in the fastest speed?\ntask = speed walking distance = 5m speed = 1.64\n2. which task and distance resulted in the slowest speed?\ntask = walking back distance = 10m speed = 0.99\n3. how far could you speed walk in 10 minutes based on your speed for the 10 - meter trial? show your work!\n4. how long would it take you to hop 30 meters based on your speed for the 5 - meter trial? show your work!\nhow far could you travel walking backwards in 15 minutes based on your results for the 5 - meter trial? show your work!\nhow long would it take you to walk (regular rate) 1 kilometer (or 1,000 m) based on your speed? show your work!\nare the results accurate? why or why not?

Answer

Explanation:

Step1: Identify the speed - distance - time formula

The formula is $d = vt$ (distance = speed×time) and $t=\frac{d}{v}$ (time = distance÷speed), where $d$ is distance, $v$ is speed and $t$ is time.

Step2: Solve question 3

Given the speed for the 10 - meter trial is $v = 0.99$ m/s (from question 2), and $t = 10$ minutes. First convert time to seconds: $t=10\times60 = 600$ s. Then use the formula $d=vt$. So $d=0.99\times600 = 594$ m.

Step3: Solve question 4

Given the speed for the 5 - meter trial is $v = 1.64$ m/s (from question 1), and $d = 30$ m. Use the formula $t=\frac{d}{v}$. So $t=\frac{30}{1.64}\approx18.29$ s.

Answer:

  1. 594 m
  2. Approximately 18.29 s