three 20.0 ohm resistors are connected in parallel and attached to a 5.00 v battery. how much current flows…

Explanation:

Step1: Calculate total resistance

For resistors in parallel, $\frac{1}{R_{total}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$. Here $R_1 = R_2=R_3 = 20.0\ \Omega$, so $\frac{1}{R_{total}}=\frac{1}{20}+\frac{1}{20}+\frac{1}{20}=\frac{3}{20}$, then $R_{total}=\frac{20}{3}\ \Omega$.

Step2: Use Ohm's law

Ohm's law is $I=\frac{V}{R}$. Given $V = 5.00\ V$ and $R = R_{total}=\frac{20}{3}\ \Omega$, so $I=\frac{5}{\frac{20}{3}}$.

Step3: Solve for current

$I=\frac{5}{\frac{20}{3}}=5\times\frac{3}{20}= 0.75\ A$.

Answer:

$0.75$