three resistors of 100, 40.0, and 10.0 ohms are in series with a 24.0 v power supply. what is their…
three resistors of 100, 40.0, and 10.0 ohms are in series with a 24.0 v power supply. what is their equivalent resistance? (unit = ohms)
Answer
Explanation:
Step1: Recall series - resistance formula
For resistors in series, the equivalent resistance $R_{eq}$ is the sum of individual resistances. The formula is $R_{eq}=R_1 + R_2+R_3$.
Step2: Substitute the given values
Given $R_1 = 100\ \Omega$, $R_2 = 40.0\ \Omega$, and $R_3 = 10.0\ \Omega$. Then $R_{eq}=100 + 40.0+10.0$.
Step3: Calculate the sum
$R_{eq}=150\ \Omega$.
Answer:
$150$