a tire at 21°c has a pressure of 0.82 atm. its temperature decreases to -3.5°c. if there is no volume change…

a tire at 21°c has a pressure of 0.82 atm. its temperature decreases to -3.5°c. if there is no volume change in the tire, what is the pressure after the temperature change? use $\frac{p_1}{t_1}=\frac{p_2}{t_2}$. 0.75 atm 0.89 atm 1.1 atm 1.3 atm

a tire at 21°c has a pressure of 0.82 atm. its temperature decreases to -3.5°c. if there is no volume change in the tire, what is the pressure after the temperature change? use $\frac{p_1}{t_1}=\frac{p_2}{t_2}$. 0.75 atm 0.89 atm 1.1 atm 1.3 atm

Answer

Explanation:

Step1: Convert temperatures to Kelvin

$T_1 = 21 + 273 = 294\ K$ $T_2=-3.5 + 273 = 269.5\ K$

Step2: Rearrange the formula to solve for $P_2$

Given $\frac{P_1}{T_1}=\frac{P_2}{T_2}$, we can get $P_2=\frac{P_1T_2}{T_1}$.

Step3: Substitute values and calculate

$P_2=\frac{0.82\times269.5}{294}$ $P_2=\frac{221.99}{294}\approx0.75\ atm$

Answer:

0.75 atm