a train moving west with an initial velocity of 20 m/s accelerates at 4 m/s² for 10 seconds. during this…

a train moving west with an initial velocity of 20 m/s accelerates at 4 m/s² for 10 seconds. during this time, the train moves a distance of meters.
Answer
Explanation:
Step1: Identify the formula
We use the kinematic - equation $d = v_0t+\frac{1}{2}at^{2}$, where $v_0$ is the initial velocity, $t$ is the time, and $a$ is the acceleration.
Step2: Substitute the given values
Given $v_0 = 20\ m/s$, $a = 4\ m/s^{2}$, and $t = 10\ s$. $d=(20\times10)+\frac{1}{2}\times4\times10^{2}$
Step3: Calculate each term
First term: $20\times10 = 200$. Second term: $\frac{1}{2}\times4\times10^{2}=2\times100 = 200$.
Step4: Find the total distance
$d=200 + 200=400$.
Answer:
400