7. a transistor radio uses 2 amps of current when it is run by a 9 volt battery. what is the resistance in…

7. a transistor radio uses 2 amps of current when it is run by a 9 volt battery. what is the resistance in the radio circuit?\n8. a current of 5 amps flows through a lamp when it is connected to a 110 volt power source. what is the resistance of the lamp?\n9. an e.m.f. of 75 volts is placed across a 15 ohm fixed resistor. what current flows through the resistor?\n10.a motor with a resistance of 32ω is connected to a voltage source. four amps of current flows in the circuit. what is the voltage of the source?\n11. a resistance of 30ω is placed in a circuit with a 90 volt battery. what current flows in the circuit?\n12.what current flows through a 15 ohm fixed resistor when it operates on a 120 volt outlet?\n13.the resistance of an electric stove burner element is 11 ohms. what current flows through this element when it runs off a 220 volt line?\n14.what voltage is applied to a 20 ohm fixed resistor if the current through the resistor is 1.5 amps?\n15.what is the resistance of a lamp that is connected to a 110 voltage source that draws 2 amps of current?
Answer
7.
Explanation:
Step1: Recall Ohm's law formula
$R=\frac{V}{I}$, where $R$ is resistance, $V$ is voltage and $I$ is current.
Step2: Substitute given values
Given $V = 9$ volts and $I=2$ amps. So $R=\frac{9}{2}= 4.5$ ohms.
Answer:
$4.5$ ohms
8.
Explanation:
Step1: Use Ohm's law formula
$R=\frac{V}{I}$
Step2: Substitute values
Given $V = 110$ volts and $I = 5$ amps. So $R=\frac{110}{5}=22$ ohms.
Answer:
$22$ ohms
9.
Explanation:
Step1: Rearrange Ohm's law for current
$I=\frac{V}{R}$
Step2: Substitute values
Given $V = 75$ volts and $R = 15$ ohms. So $I=\frac{75}{15}=5$ amps.
Answer:
$5$ amps
10.
Explanation:
Step1: Use Ohm's law formula
$V=IR$
Step2: Substitute values
Given $I = 4$ amps and $R=32$ ohms. So $V=4\times32 = 128$ volts.
Answer:
$128$ volts
11.
Explanation:
Step1: Rearrange Ohm's law for current
$I=\frac{V}{R}$
Step2: Substitute values
Given $V = 90$ volts and $R = 30$ ohms. So $I=\frac{90}{30}=3$ amps.
Answer:
$3$ amps
12.
Explanation:
Step1: Rearrange Ohm's law for current
$I=\frac{V}{R}$
Step2: Substitute values
Given $V = 120$ volts and $R = 15$ ohms. So $I=\frac{120}{15}=8$ amps.
Answer:
$8$ amps
13.
Explanation:
Step1: Rearrange Ohm's law for current
$I=\frac{V}{R}$
Step2: Substitute values
Given $V = 220$ volts and $R = 11$ ohms. So $I=\frac{220}{11}=20$ amps.
Answer:
$20$ amps
14.
Explanation:
Step1: Use Ohm's law formula
$V=IR$
Step2: Substitute values
Given $I = 1.5$ amps and $R = 20$ ohms. So $V=1.5\times20=30$ volts.
Answer:
$30$ volts
15.
Explanation:
Step1: Recall Ohm's law formula
$R=\frac{V}{I}$
Step2: Substitute given values
Given $V = 110$ volts and $I=2$ amps. So $R=\frac{110}{2}=55$ ohms.
Answer:
$55$ ohms