a truck heading east has an initial velocity of 6 m/s. it accelerates at 2 m/s² for 12 seconds. what…

Answer:

D. 360 m

Explanation:

Step1: Identify the kinematic - equation

We use the equation $d = v_0t+\frac{1}{2}at^{2}$, where $d$ is the distance, $v_0$ is the initial velocity, $t$ is the time, and $a$ is the acceleration.

Step2: Substitute the given values

Given $v_0 = 6\ m/s$, $a = 2\ m/s^{2}$, and $t = 12\ s$. $d=(6\times12)+\frac{1}{2}\times2\times12^{2}$

Step3: Calculate the first - term

$6\times12 = 72$

Step4: Calculate the second - term

$\frac{1}{2}\times2\times12^{2}=1\times144 = 144$

Step5: Find the total distance

$d=72 + 288=360\ m$