two children are throwing a baseball back and forth. the ball is 4 ft above the ground when it leaves one…

two children are throwing a baseball back and forth. the ball is 4 ft above the ground when it leaves one childs hand with an upward velocity of 36 ft/s. if acceleration due to gravity is -16 ft/s², how high above the ground is the ball 2 s after it is thrown?\nh(t)=at² + vt+h₀\n12 ft\n20 ft\n76 ft\n116 ft

two children are throwing a baseball back and forth. the ball is 4 ft above the ground when it leaves one childs hand with an upward velocity of 36 ft/s. if acceleration due to gravity is -16 ft/s², how high above the ground is the ball 2 s after it is thrown?\nh(t)=at² + vt+h₀\n12 ft\n20 ft\n76 ft\n116 ft

Answer

Answer:

C. 76 ft

Explanation:

Step1: Identify the values

$a=-16$, $v = 36$, $h_0=4$, $t = 2$

Step2: Substitute into the formula

$h(t)=-16t^{2}+36t + 4$ Substitute $t = 2$: $h(2)=-16\times2^{2}+36\times2 + 4$

Step3: Calculate the powers

$h(2)=-16\times4+36\times2 + 4$

Step4: Perform multiplications

$h(2)=-64 + 72+4$

Step5: Perform additions

$h(2)=8 + 4=76$