two point charges each with ( 5.0\times10^{-2} c ) of charge are ( 5.0\times10^{-2} m ) apart. knowing that…

two point charges each with ( 5.0\times10^{-2} c ) of charge are ( 5.0\times10^{-2} m ) apart. knowing that ( k ) is ( 9\times10^{9} ncdot m^{2}/c^{2} ) (the proportionality constant for coulombs law), find the force between the charges. express your answer to two significant figures and include the appropriate units. ( f = )

two point charges each with ( 5.0\times10^{-2} c ) of charge are ( 5.0\times10^{-2} m ) apart. knowing that ( k ) is ( 9\times10^{9} ncdot m^{2}/c^{2} ) (the proportionality constant for coulombs law), find the force between the charges. express your answer to two significant figures and include the appropriate units. ( f = )

Answer

Explanation:

Step1: Recall Coulomb's law formula

Coulomb's law is given by ( F = k\frac{q_1q_2}{r^2} ). Here, ( q_1 = q_2=5.0\times 10^{-2}\space C ), ( r = 5.0\times 10^{-2}\space m ), and ( k = 9\times 10^{9}\space N\cdot m^{2}/C^{2} ).

Step2: Substitute the values into the formula

Substitute the values: [ \begin{align*} F&=(9\times 10^{9})\frac{(5.0\times 10^{-2})(5.0\times 10^{-2})}{(5.0\times 10^{-2})^{2}}\ &=(9\times 10^{9})\frac{25\times 10^{-4}}{25\times 10^{-4}}\ &=9\times 10^{9}\space N \end{align*} ] Rounding to two significant figures, ( F = 9.0\times 10^{9}\space N )

Answer:

Value: ( 9.0\times 10^{9} ), Units: ( N )