two pots with different amounts of water are heated by identical flames for several minutes. which one has…

Explanation:

Step1: Recall heat - mass - temperature relationship

The heat formula is $Q = mc\Delta T$, where $Q$ is heat, $m$ is mass, $c$ is specific heat capacity (constant for water), and $\Delta T$ is change in temperature. Given identical flames, $Q$ is the same for both pots, and $c$ is the same for water in both pots. Pot B has less water, so $m$ is smaller for pot B.

Step2: Analyze the change in temperature

From $Q = mc\Delta T$, we can express $\Delta T=\frac{Q}{mc}$. Since $Q$ and $c$ are the same and $m$ is smaller for pot B, $\Delta T$ (change in temperature) is larger for pot B.

Answer:

Pot B