two teams are playing tug of war. team a pulls to the right with a force of 450 n. team b pulls to the left…

two teams are playing tug of war. team a pulls to the right with a force of 450 n. team b pulls to the left with a force of 415 n. what is the net force on the rope, and what is its direction? 35 n to the right 35 n to the left 865 n to the right 865 n to the left

Answer

Explanation:

Step1: Define forces

Let the force by Team A be $F_A = 450$ N (right - direction is positive) and the force by Team B be $F_B=- 415$ N (left - direction is negative).

Step2: Calculate net force

The net force $F_{net}$ is given by $F_{net}=F_A + F_B$. Substitute the values: $F_{net}=450+( - 415)$. $F_{net}=450 - 415=35$ N. Since the result is positive, the direction is to the right.

Answer:

35 N to the right