type the correct answer in the box. a book that weighs 0.35 kilograms is kept on a shelf thats 2.0 meters…

type the correct answer in the box. a book that weighs 0.35 kilograms is kept on a shelf thats 2.0 meters above the ground. a picture frame that weighs 0.5 kilograms will have the same gravitational potential energy as the book when its raised to a height of meters. (use $pe = m\times g\times h$, where $g = 9.8 n/kg$.)

type the correct answer in the box. a book that weighs 0.35 kilograms is kept on a shelf thats 2.0 meters above the ground. a picture frame that weighs 0.5 kilograms will have the same gravitational potential energy as the book when its raised to a height of meters. (use $pe = m\times g\times h$, where $g = 9.8 n/kg$.)

Answer

Explanation:

Step1: Calculate book's PE

Let $m_1 = 0.35$ kg, $h_1=2.0$ m and $g = 9.8$ N/kg. Using $PE=m\times g\times h$, the potential - energy of the book $PE_1=m_1\times g\times h_1$. $PE_1 = 0.35\times9.8\times2.0=6.86$ J

Step2: Find height for picture - frame

Let the mass of the picture - frame $m_2 = 0.5$ kg, and we want $PE_2 = PE_1 = 6.86$ J. Using $PE=m\times g\times h$, we can solve for $h_2$. $h_2=\frac{PE_2}{m_2\times g}$ Substitute $PE_2 = 6.86$ J, $m_2 = 0.5$ kg and $g = 9.8$ N/kg into the formula: $h_2=\frac{6.86}{0.5\times9.8}=\frac{6.86}{4.9}=1.4$ m

Answer:

$1.4$