type the correct answer in the box. express your answer to three significant figures.\nthe half - life of…

type the correct answer in the box. express your answer to three significant figures.\nthe half - life of carbon - 14 is 5,730 years. dating organic material by looking for c - 14 cant be accurately done after 50,000 years.\nsuppose a fossilized tree branch originally contained 4.30 grams of c - 14. how much c - 14 would be left after 50,000 years?\nuse the formula $n = n_0(\frac{1}{2})^{\frac{t}{t}}$.\na tree branch that originally had 4.3 grams of carbon - 14 will have grams after 50,000 years.

type the correct answer in the box. express your answer to three significant figures.\nthe half - life of carbon - 14 is 5,730 years. dating organic material by looking for c - 14 cant be accurately done after 50,000 years.\nsuppose a fossilized tree branch originally contained 4.30 grams of c - 14. how much c - 14 would be left after 50,000 years?\nuse the formula $n = n_0(\frac{1}{2})^{\frac{t}{t}}$.\na tree branch that originally had 4.3 grams of carbon - 14 will have grams after 50,000 years.

Answer

Explanation:

Step1: Identify the values

$N_0 = 4.30$ grams, $t = 50000$ years, $T=5730$ years.

Step2: Substitute into the formula

$N = N_0(\frac{1}{2})^{\frac{t}{T}}=4.30\times(\frac{1}{2})^{\frac{50000}{5730}}$.

Step3: Calculate the exponent

$\frac{50000}{5730}\approx8.726$.

Step4: Calculate the power of $\frac{1}{2}$

$(\frac{1}{2})^{8.726}\approx0.00207$.

Step5: Calculate the remaining amount

$N = 4.30\times0.00207 = 0.00889$ grams.

Answer:

$0.00889$