type the correct answer in the box. express your answer to three significant figures.\nthe gas inside a…
type the correct answer in the box. express your answer to three significant figures.\nthe gas inside a large engine cylinder initially has a pressure of 105 kilopascals and a volume of 2.031 liters. if the gas is compressed at constant temperature to a volume of 0.356 liter, what is its new pressure?\nthe pressure of the compressed gas is kilopascal
Answer
Answer:
601
Explanation:
Step1: Identify the law
Boyle's law: $P_1V_1 = P_2V_2$.
Step2: Define the variables
$P_1 = 105$ kPa, $V_1=2.031$ L, $V_2 = 0.356$ L, $P_2$ is unknown.
Step3: Rearrange the formula for $P_2$
$P_2=\frac{P_1V_1}{V_2}$.
Step4: Substitute the values
$P_2=\frac{105\times2.031}{0.356}$. $P_2=\frac{213.255}{0.356}\approx601.84$.
Step5: Round to three - significant figures
$P_2 = 601$ kPa.