2. an unbalanced force of 20. newtons is applied to a mass of $1.0 \\times 10^{3}$ kilograms. after 10…

2. an unbalanced force of 20. newtons is applied to a mass of $1.0 \\times 10^{3}$ kilograms. after 10. seconds, how much will the momentum of the mass have changed by?

2. an unbalanced force of 20. newtons is applied to a mass of $1.0 \\times 10^{3}$ kilograms. after 10. seconds, how much will the momentum of the mass have changed by?

Answer

Explanation:

Step1: Identify the impulse-momentum theorem

The change in momentum ($\Delta p$) is equal to the impulse ($J$) applied to the object. $$J = \Delta p$$

Step2: Use the formula for impulse

Impulse is the product of the average force ($F$) and the time interval ($\Delta t$) over which it acts. $$J = F \cdot \Delta t$$

Step3: Substitute the given values

Substitute $F = 20\text{ N}$ and $\Delta t = 10\text{ s}$ into the equation. $$\Delta p = 20\text{ N} \times 10\text{ s}$$

Step4: Calculate the final value

Multiply the values to find the change in momentum. $$\Delta p = 200\text{ kg}\cdot\text{m/s}$$

Answer:

200 kg·m/s