uranium-232 has a half - life of 68.8 years. after 344.0 years, how much uranium-232 will remain from a…

Explanation:

Step1: Calculate number of half - lives

The formula to find the number of half - lives $n$ is $n=\frac{t}{T_{1/2}}$, where $t$ is the time elapsed and $T_{1/2}$ is the half - life. Given $t = 344.0$ years and $T_{1/2}=68.8$ years. $n=\frac{344.0}{68.8}=5$

Step2: Calculate remaining amount

The formula for the remaining amount $A$ of a radioactive substance is $A = A_0\times(\frac{1}{2})^n$, where $A_0$ is the initial amount and $n$ is the number of half - lives. Given $A_0 = 100.0$ g and $n = 5$. $A=100.0\times(\frac{1}{2})^5=100.0\times\frac{1}{32}=3.125\approx3.13$ g

Answer:

3.13 g