(5) use the diagram below to determine the the average speed and velocity of the boy as he runs from point a…

(5) use the diagram below to determine the the average speed and velocity of the boy as he runs from point a to point b to point c and then to point d in 18 seconds.
Answer
Answer:
Average speed: $\frac{25}{18}\text{ m/s}\approx1.39\text{ m/s}$, Average velocity: $\frac{15}{18}\text{ m/s}=\frac{5}{6}\text{ m/s}\approx0.83\text{ m/s}$
Explanation:
Step1: Calculate total distance
Distance from A to B is $10 - (- 5)=15$ m, from B to D is $10 - 5 = 5$ m, from D to C is $5-0 = 5$ m. Total distance $d=15 + 5+5=25$ m.
Step2: Calculate displacement
Displacement is the straight - line distance from the starting point to the ending point. Starting at A(-5 m) and ending at C(0 m), displacement $\Delta x=0-(-5)=5$ m.
Step3: Calculate average speed
Average speed formula is $v_{avg - speed}=\frac{d}{t}$. Given $t = 18$ s and $d = 25$ m, so $v_{avg - speed}=\frac{25}{18}\text{ m/s}$.
Step4: Calculate average velocity
Average velocity formula is $v_{avg - velocity}=\frac{\Delta x}{t}$. Given $t = 18$ s and $\Delta x = 15$ m, so $v_{avg - velocity}=\frac{15}{18}=\frac{5}{6}\text{ m/s}$.