use the friction simulation. place the fridge on the surface. apply a 500 n pushing force. use the…

use the friction simulation. place the fridge on the surface. apply a 500 n pushing force. use the acceleration due to gravity as $g = 9.8\frac{m}{s^{2}}$. what is the minimum coefficient of static friction that can prevent it from moving when experiencing a 500n applied force? (how much grip does the floor need to have to

use the friction simulation. place the fridge on the surface. apply a 500 n pushing force. use the acceleration due to gravity as $g = 9.8\frac{m}{s^{2}}$. what is the minimum coefficient of static friction that can prevent it from moving when experiencing a 500n applied force? (how much grip does the floor need to have to

Answer

Explanation:

Step1: Calculate the normal force

The normal force $N$ on a flat - surface is equal to the weight of the object. Using the formula $N = mg$, where $m = 200$ kg and $g=9.8$ m/s². So $N=200\times9.8 = 1960$ N.

Step2: Use the static - friction formula

The maximum static - friction force $F_f=\mu_sN$, where $\mu_s$ is the coefficient of static friction. When the object is on the verge of moving, the maximum static - friction force is equal to the applied force. We know $F_f = 500$ N and $N = 1960$ N. From $F_f=\mu_sN$, we can solve for $\mu_s$. Rearranging the formula gives $\mu_s=\frac{F_f}{N}$.

Step3: Calculate the coefficient of static friction

Substitute $F_f = 500$ N and $N = 1960$ N into the formula $\mu_s=\frac{F_f}{N}$, we get $\mu_s=\frac{500}{1960}\approx0.255$.

Answer:

$0.255$