use the graph to answer the question. what is the total displacement of the object after 5 seconds? velocity…

Explanation:

Step1: Recall displacement - velocity relation

Displacement is the area under the velocity - time graph.

Step2: Identify the shape of the area

The area under the velocity - time graph from (t = 0) to (t=5) s is a trapezoid.

Step3: Use the trapezoid area formula

The formula for the area of a trapezoid is (A=\frac{(a + b)h}{2}), where (a) and (b) are the lengths of the parallel sides and (h) is the height. Here, (a = 10) m/s, (b=55) m/s, and (h = 5) s. [A=\frac{(10 + 55)\times5}{2}] [A=\frac{65\times5}{2}=\frac{325}{2}=162.5]

Answer:

162.5