do not use negatives for used values when entering numbers in the chart below.\nwhat voltage is left after…

Explanation:

Step1: Calculate total resistance

The resistors are in series. So, $R_{total}=R1 + R2+R3=10\Omega+10\Omega + 43\Omega=63\Omega$.

Step2: Calculate total current using Ohm's law

Ohm's law is $I=\frac{V}{R}$. Given $V = 43V$ and $R = R_{total}=63\Omega$, so $I=\frac{43V}{63\Omega}\approx0.683A$.

Step3: Calculate voltage across each resistor

For $R1$: Using $V = IR$, $V1=I\times R1=0.683A\times10\Omega = 6.83V$. For $R2$: $V2=I\times R2=0.683A\times10\Omega = 6.83V$. For $R3$: $V3=I\times R3=0.683A\times43\Omega\approx29.37V$.

Step4: Calculate voltage left after each resistor

Voltage left after $R1$: $V_{left1}=43V - 6.83V = 36.17V$. Voltage left after $R2$: $V_{left2}=36.17V - 6.83V = 29.34V$. Voltage left after $R3$: $V_{left3}=29.34V - 29.37V = 0V$.

For the table:

	V (V)	I (A)	R ($\Omega$)	P (W)
1	6.83	0.683	10	$P1=V1\times I = 6.83V\times0.683A\approx4.67W$
2	6.83	0.683	10	$P2=V2\times I = 6.83V\times0.683A\approx4.67W$
3	29.37	0.683	43	$P3=V3\times I = 29.37V\times0.683A\approx20.06W$
Total	43	0.683	63	$P_{total}=V_{total}\times I = 43V\times0.683A\approx29.37W$

Answer:

Voltage left after $R1$: $36.17V$ Voltage left after $R2$: $29.34V$ Voltage left after $R3$: $0V$ Table values as shown above.