when using a calorimeter, the initial temperature of a metal is 70.4°c. the initial temperature of the water…

when using a calorimeter, the initial temperature of a metal is 70.4°c. the initial temperature of the water is 23.6°c. at the end of the experiment, the final equilibrium temperature of the water is 29.8°c. what is the final temperature of the metal? °c what is the temperature change of the water? °c what is the temperature change of the metal? °c

when using a calorimeter, the initial temperature of a metal is 70.4°c. the initial temperature of the water is 23.6°c. at the end of the experiment, the final equilibrium temperature of the water is 29.8°c. what is the final temperature of the metal? °c what is the temperature change of the water? °c what is the temperature change of the metal? °c

Answer

Explanation:

Step1: Determine final metal temperature

In a calorimetry experiment, at equilibrium, the final temperature of the metal is the same as the final temperature of the water. So the final temperature of the metal is $29.8^{\circ}C$.

Step2: Calculate water temperature - change

The formula for temperature - change is $\Delta T=T_{final}-T_{initial}$. For water, $T_{initial} = 23.6^{\circ}C$ and $T_{final}=29.8^{\circ}C$. So $\Delta T_{water}=29.8 - 23.6=6.2^{\circ}C$.

Step3: Calculate metal temperature - change

For the metal, $T_{initial} = 70.4^{\circ}C$ and $T_{final}=29.8^{\circ}C$. Using the formula $\Delta T=T_{final}-T_{initial}$, we get $\Delta T_{metal}=29.8 - 70.4=-40.6^{\circ}C$.

Answer:

Final temperature of the metal: $29.8$ Temperature change of the water: $6.2$ Temperature change of the metal: $- 40.6$