using ohms law, explain why bulb a is brighter than bulb b.\na) bulb a has higher resistance, less…

using ohms law, explain why bulb a is brighter than bulb b.\na) bulb a has higher resistance, less current\nb) bulb a has lower resistance, more current\nc) bulb a has higher resistance, more current\nd) bulb a has lower resistance, less current

using ohms law, explain why bulb a is brighter than bulb b.\na) bulb a has higher resistance, less current\nb) bulb a has lower resistance, more current\nc) bulb a has higher resistance, more current\nd) bulb a has lower resistance, less current

Answer

Brief Explanations:

Ohm's law is $V = IR$ (where $V$ is voltage, $I$ is current, and $R$ is resistance). In a circuit with constant voltage, current and resistance are inversely - proportional. Brighter bulbs have more power, and power $P=VI$. More current means more power for the same voltage. So a bulb with lower resistance will have more current flowing through it and will be brighter.

Answer:

B. Bulb A has lower resistance, more current