voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. the wavelength changes…

voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. the wavelength changes from 2 m in the air to 8 m underwater. how has the change in media affected the frequency of the wave? it increased. it decreased. it stayed the same. it cannot be calculated.

voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. the wavelength changes from 2 m in the air to 8 m underwater. how has the change in media affected the frequency of the wave? it increased. it decreased. it stayed the same. it cannot be calculated.

Answer

Explanation:

Step1: Recall wave - speed formula

The wave - speed formula is $v = f\lambda$, where $v$ is the wave speed, $f$ is the frequency, and $\lambda$ is the wavelength.

Step2: Calculate frequency in air

In air, $v_{air}=400\ m/s$ and $\lambda_{air} = 2\ m$. Using $v = f\lambda$, we get $f_{air}=\frac{v_{air}}{\lambda_{air}}=\frac{400}{2}=200\ Hz$.

Step3: Calculate frequency underwater

Underwater, $v_{water}=1600\ m/s$ and $\lambda_{water}=8\ m$. Using $v = f\lambda$, we get $f_{water}=\frac{v_{water}}{\lambda_{water}}=\frac{1600}{8}=200\ Hz$.

Answer:

It stayed the same.