the voltage across the primary winding is 350,000 v, and the voltage across the secondary winding is 17,500…

the voltage across the primary winding is 350,000 v, and the voltage across the secondary winding is 17,500 v. if the secondary winding has 600 coils, how many coils are in the primary winding?\n30 coils\n583 coils\n12,000 coils\n332,500 coils

the voltage across the primary winding is 350,000 v, and the voltage across the secondary winding is 17,500 v. if the secondary winding has 600 coils, how many coils are in the primary winding?\n30 coils\n583 coils\n12,000 coils\n332,500 coils

Answer

Explanation:

Step1: Recall transformer - voltage ratio formula

The formula for a transformer is $\frac{V_p}{V_s}=\frac{N_p}{N_s}$, where $V_p$ is the primary - voltage, $V_s$ is the secondary - voltage, $N_p$ is the number of primary coils, and $N_s$ is the number of secondary coils.

Step2: Rearrange the formula to solve for $N_p$

We can rewrite the formula as $N_p=\frac{V_p\times N_s}{V_s}$.

Step3: Substitute the given values

Given $V_p = 350000$ V, $V_s=17500$ V, and $N_s = 600$ coils. Then $N_p=\frac{350000\times600}{17500}$. First, calculate $350000\times600 = 210000000$. Then, $\frac{210000000}{17500}=12000$.

Answer:

12,000 coils