if voltage in a circuit is constant, the current can be cut to half of its original value by changing the…

if voltage in a circuit is constant, the current can be cut to half of its original value by changing the resistance to ________ its original value. which best completes the statement? one - fourth one - half two times four times

if voltage in a circuit is constant, the current can be cut to half of its original value by changing the resistance to ________ its original value. which best completes the statement? one - fourth one - half two times four times

Answer

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is $V = IR$, where $V$ is voltage, $I$ is current and $R$ is resistance.

Step2: Let the initial current be $I_1$ and resistance be $R_1$

So $V=I_1R_1$.

Step3: Let the new current be $I_2=\frac{1}{2}I_1$ and new resistance be $R_2$

Since $V$ is constant, $V = I_2R_2$. And because $V = I_1R_1$ and $V = I_2R_2$, we have $I_1R_1=I_2R_2$.

Step4: Substitute $I_2=\frac{1}{2}I_1$ into $I_1R_1=I_2R_2$

$I_1R_1=\frac{1}{2}I_1R_2$.

Step5: Solve for $R_2$

Divide both sides of the equation $I_1R_1=\frac{1}{2}I_1R_2$ by $I_1$ (assuming $I_1\neq0$), we get $R_2 = 2R_1$.

Answer:

C. two times