the volume of a gas changed from 1145 ml to 765 ml. the final temperature of the gas is 640 k. what was the…

the volume of a gas changed from 1145 ml to 765 ml. the final temperature of the gas is 640 k. what was the original temperature of the gas? t = ? k assume that the number of moles and the pressure remain constant.

the volume of a gas changed from 1145 ml to 765 ml. the final temperature of the gas is 640 k. what was the original temperature of the gas? t = ? k assume that the number of moles and the pressure remain constant.

Answer

Explanation:

Step1: Identify the gas - law formula

Since the number of moles and pressure are constant, we use Charles's law: $\frac{V_1}{T_1}=\frac{V_2}{T_2}$.

Step2: Rearrange the formula for $T_1$

$T_1=\frac{V_1T_2}{V_2}$.

Step3: Substitute the given values

$V_1 = 1145\ mL$, $V_2=765\ mL$, $T_2 = 640\ K$. So $T_1=\frac{1145\times640}{765}$.

Step4: Calculate the value of $T_1$

$T_1=\frac{732800}{765}\approx958\ K$.

Answer:

$958$