the volume of a gas is changed from 3.6 l to 15.5 l. what is the initial temperature of the gas if the final…

the volume of a gas is changed from 3.6 l to 15.5 l. what is the initial temperature of the gas if the final temperature is 87 °c?\nt = ? °c\nassume that the number of moles and the pressure remain constant.
Answer
Explanation:
Step1: Convert final temperature to Kelvin
$T_2 = 87 + 273.15=360.15\ K$
Step2: Apply Charles's Law ($\frac{V_1}{T_1}=\frac{V_2}{T_2}$)
$T_1=\frac{V_1T_2}{V_2}$
Step3: Substitute values
$T_1=\frac{3.6\times360.15}{15.5}\approx83.3\ K$
Step4: Convert back to Celsius
$T_1 = 83.3 - 273.15=-189.85^{\circ}C$
Answer:
$-189.85$