when the volume of a gas is changed from 3.75 l to 6.52 l, the temperature changes from 65.0 °c to a new…

when the volume of a gas is changed from 3.75 l to 6.52 l, the temperature changes from 65.0 °c to a new value. what is the final temperature of the gas? t = ? °c assume that the number of moles and the pressure remain constant. be careful of the temperature units.

when the volume of a gas is changed from 3.75 l to 6.52 l, the temperature changes from 65.0 °c to a new value. what is the final temperature of the gas? t = ? °c assume that the number of moles and the pressure remain constant. be careful of the temperature units.

Answer

Explanation:

Step1: Convert initial temperature to Kelvin

$T_1=(65.0 + 273.15)\text{ K}=338.15\text{ K}$

Step2: Apply Charles's Law ($\frac{V_1}{T_1}=\frac{V_2}{T_2}$)

$T_2=\frac{V_2T_1}{V_1}$

Step3: Substitute values

$T_2=\frac{6.52\text{ L}\times338.15\text{ K}}{3.75\text{ L}}\approx587.9\text{ K}$

Step4: Convert final temperature to Celsius

$T_2=(587.9 - 273.15)^{\circ}\text{C}\approx314.8^{\circ}\text{C}$

Answer:

$314.8$