the volume of a gas decreases to half of its original volume, but the gas maintains the same number of moles…

the volume of a gas decreases to half of its original volume, but the gas maintains the same number of moles and temperature. according to the ideal gas law, what will most likely happen to the pressure?\nit will double.\nit will decrease.\nit will increase slightly.\nit will remain the same.

the volume of a gas decreases to half of its original volume, but the gas maintains the same number of moles and temperature. according to the ideal gas law, what will most likely happen to the pressure?\nit will double.\nit will decrease.\nit will increase slightly.\nit will remain the same.

Answer

Explanation:

Step1: Write the ideal - gas law

The ideal - gas law is $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal - gas constant, and $T$ is temperature.

Step2: Analyze the changes

We know that $n$ and $T$ are constant, and $V$ becomes $\frac{V}{2}$. Let the initial state be $P_1V_1=nRT$ and the final state be $P_2V_2=nRT$. Since $nRT$ is constant in both cases, $P_1V_1 = P_2V_2$. Substituting $V_2=\frac{V_1}{2}$ into the equation, we get $P_1V_1 = P_2\times\frac{V_1}{2}$.

Step3: Solve for $P_2$

Dividing both sides of the equation $P_1V_1 = P_2\times\frac{V_1}{2}$ by $\frac{V_1}{2}$ (assuming $V_1\neq0$), we have $P_2 = 2P_1$.

Answer:

It will double.