what is the volume of a sphere with a radius of 9.5 ft, rounded to the nearest tenth of a cubic foot?

what is the volume of a sphere with a radius of 9.5 ft, rounded to the nearest tenth of a cubic foot?
Answer
Explanation:
Step1: Recall sphere volume formula
The formula for the volume $V$ of a sphere is $V = \frac{4}{3}\pi r^3$, where $r$ is the radius.
Step2: Substitute radius $r=9.5$ ft
$$V = \frac{4}{3}\pi (9.5)^3$$ First calculate $(9.5)^3 = 9.5 \times 9.5 \times 9.5 = 857.375$
Step3: Compute intermediate volume value
$$V = \frac{4}{3}\pi \times 857.375 = \frac{3429.5}{3}\pi \approx 1143.1667 \times 3.1416$$ $$V \approx 3591.67$$
Step4: Round to nearest tenth
Round $3591.67$ to one decimal place.
Answer:
$3591.7$ cubic feet