while on a boat tour along the coast of the atlantic ocean, leo sees a great white shark jump out of the…

while on a boat tour along the coast of the atlantic ocean, leo sees a great white shark jump out of the water. the shark travels upward with a velocity of 18 feet per second before splashing back down into the water. to the nearest tenth of a second, how long is the shark in the air? hint: use the formula h = -16t² + vt + s.

while on a boat tour along the coast of the atlantic ocean, leo sees a great white shark jump out of the water. the shark travels upward with a velocity of 18 feet per second before splashing back down into the water. to the nearest tenth of a second, how long is the shark in the air? hint: use the formula h = -16t² + vt + s.

Answer

Explanation:

Step1: Identify the values

The initial - velocity $v = 18$ feet per second, and the initial height $s = 0$ (assuming the water - level as the starting height), and when the shark splashes back into the water, $h = 0$. The formula is $h=-16t^{2}+vt + s$. Substituting the values, we get $0=-16t^{2}+18t+0$.

Step2: Solve the quadratic equation

We have the quadratic equation $-16t^{2}+18t = 0$. Factor out a $t$: $t(-16t + 18)=0$. This gives two solutions for $t$: $t = 0$ (corresponds to the time when the shark starts the jump) and $-16t+18 = 0$. Solving $-16t+18 = 0$ for $t$: [ \begin{align*} -16t&=-18\ t&=\frac{18}{16}=\frac{9}{8}=1.125 \end{align*} ]

Step3: Round the answer

Rounding $t = 1.125$ to the nearest tenth of a second, we get $t\approx1.1$ seconds.

Answer:

$1.1$