during wwii, the air force administrators noticed that a large number of fighter pilots were being killed…

during wwii, the air force administrators noticed that a large number of fighter pilots were being killed because they were not dark - adapted during night air raids. an experiment was performed to determine whether different levels of preflight illumination might result in significant differences in time to dark adaptation. twenty - four pilots were randomly and equally assigned to one of three treatment groups. group a spent 30 minutes in a brightly lighted room; group b spent 30 minutes in a dimly lighted room; group c spent 30 minutes in a brightly lighted room wearing red - tinted goggles. the length of time in minutes for complete dark adaptation was recorded for each pilot. the results were found to be: f(2,21)=1.09, p>.05. based on these results, the next step should be ___.\npost hoc tests to determine where the differences lie.\nfisher lsd to determine where differences lie.\nfisher lsd since ho was retained.\nnothing since overall anova was nonsignificant.

during wwii, the air force administrators noticed that a large number of fighter pilots were being killed because they were not dark - adapted during night air raids. an experiment was performed to determine whether different levels of preflight illumination might result in significant differences in time to dark adaptation. twenty - four pilots were randomly and equally assigned to one of three treatment groups. group a spent 30 minutes in a brightly lighted room; group b spent 30 minutes in a dimly lighted room; group c spent 30 minutes in a brightly lighted room wearing red - tinted goggles. the length of time in minutes for complete dark adaptation was recorded for each pilot. the results were found to be: f(2,21)=1.09, p>.05. based on these results, the next step should be ___.\npost hoc tests to determine where the differences lie.\nfisher lsd to determine where differences lie.\nfisher lsd since ho was retained.\nnothing since overall anova was nonsignificant.

Answer

Answer:

nothing since overall ANOVA was nonsignificant.

Explanation:

Step1: Analyze ANOVA result

The F - statistic is (F(2,21) = 1.09) and (p>0.05). This means the null hypothesis (no difference between group means) is not rejected in the overall ANOVA test.

Step2: Consider post - hoc tests

Post - hoc tests (like Fisher LSD or other post - hoc procedures) are used to find where the differences lie when the overall ANOVA is significant. Since the overall ANOVA here is non - significant, there is no need for post - hoc tests. So the next step is nothing.