you have 7,160 grams of a radioactive kind of bismuth. how much will be left after 10 days if its half…

Explanation:

Step1: Calculate number of half - lives

The half - life is 5 days and the time elapsed is 10 days. The number of half - lives $n=\frac{10}{5}=2$.

Step2: Use radioactive decay formula

The initial amount $N_0 = 7160$ grams. The formula for radioactive decay is $N = N_0\times(\frac{1}{2})^n$. Substitute $N_0 = 7160$ and $n = 2$ into the formula: $N=7160\times(\frac{1}{2})^2$. $N = 7160\times\frac{1}{4}$. $N = 1790$.

Answer:

1790