you have 979,584 grams of a radioactive kind of argon. if its half - life is 2 hours, how much will be left…

Explanation:

Step1: Calculate number of half - lives

The half - life is 2 hours and the time elapsed is 10 hours. The number of half - lives $n=\frac{10}{2}=5$.

Step2: Use the radioactive decay formula

The formula for radioactive decay is $A = A_0\times(\frac{1}{2})^n$, where $A_0$ is the initial amount and $n$ is the number of half - lives. Here, $A_0 = 979584$ grams and $n = 5$. So $A=979584\times(\frac{1}{2})^5$.

Step3: Calculate the remaining amount

$(\frac{1}{2})^5=\frac{1}{32}$, and $A = 979584\times\frac{1}{32}=30612$.

Answer:

30612