if you place a +0.638 c charge at a point where the electric field is 27.4 n/c to the right, what electric…

if you place a +0.638 c charge at a point where the electric field is 27.4 n/c to the right, what electric force will it feel? include a + or - sign to indicate the direction of the force. (unit = n)

if you place a +0.638 c charge at a point where the electric field is 27.4 n/c to the right, what electric force will it feel? include a + or - sign to indicate the direction of the force. (unit = n)

Answer

Explanation:

Step1: Recall the formula

The formula for electric force is $F = qE$, where $F$ is the electric force, $q$ is the charge, and $E$ is the electric - field strength.

Step2: Substitute the given values

Given $q = + 0.638\ C$ and $E=27.4\ N/C$. Substitute these values into the formula: $F=(+0.638\ C)\times(27.4\ N/C)$.

Step3: Calculate the force

$F = 0.638\times27.4=17.5812\ N$. Since both the charge and the electric - field are in the positive direction (the electric field is to the right and the charge is positive), the force is positive.

Answer:

$+ 17.5812\ N$