9. if you place a 2 kg textbook on a scale inside of an elevator, and it reads 23 n. describe the motion of…

9. if you place a 2 kg textbook on a scale inside of an elevator, and it reads 23 n. describe the motion of the elevator: the elevator is at rest the elevator is moving at a constant velocity the elevator is accelerating downwards the elevator is accelerating upwards clear all

9. if you place a 2 kg textbook on a scale inside of an elevator, and it reads 23 n. describe the motion of the elevator: the elevator is at rest the elevator is moving at a constant velocity the elevator is accelerating downwards the elevator is accelerating upwards clear all

Answer

Explanation:

Step1: Calculate the normal weight

The normal weight of the textbook is $F = mg$, where $m = 2$ kg and $g= 9.8$ m/s². So $F=2\times9.8 = 19.6$ N.

Step2: Analyze the scale - reading

The scale reads 23 N, which is greater than the normal weight of the textbook. According to Newton's second - law $F_{net}=ma$, when the normal force $N$ (scale reading) is greater than the weight $mg$, the net force is upwards. That is $N - mg=ma$ (where $N$ is the normal force exerted by the scale on the textbook), and $a=\frac{N - mg}{m}>0$. A positive acceleration means the elevator is accelerating upwards.

Answer:

The elevator is accelerating upwards