1. (02.02 mc) the following are beginning salaries for a certain industry in different areas: $26,150.00…

1. (02.02 mc) the following are beginning salaries for a certain industry in different areas: $26,150.00 $19,350.00 $31,460.00 $27,910.00 $29,920.00 $27,910.00 $35,630.00 $31,460.00 find the median of the data set. (2 points) $27,910.00 $28,915.00 $22,552.00 $59,370.00 2. (02.02 lc) the beginning mean wage in a certain industry is $35,240.00. if the mean wage grows by 5.125%, what is the new mean wage? (2 points) $31,453.35 $33,433.95 $37,046.05 $42,567.98
Answer
Explanation:
Step1: Arrange data in ascending order
$19,350.00, $26,150.00, $27,910.00, $27,910.00, $29,920.00, $31,460.00, $31,460.00, $35,630.00, $59,370.00, $222,552.00, $28,915.00
After arranging: $19,350.00, $26,150.00, $27,910.00, $27,910.00, $28,915.00, $29,920.00, $31,460.00, $31,460.00, $35,630.00, $59,370.00, $222,552.00
Step2: Find the median
Since there are 11 data - points (an odd number), the median is the $\left(\frac{n + 1}{2}\right)$-th value. Here $n=11$, so $\frac{11 + 1}{2}=6$th value. The 6th value in the ordered list is $29,920.00$
Answer:
$29,920.00$
Explanation for second - part:
Step1: Calculate the new mean
The initial mean is $35,240.00$. The mean grows by 5.125%. The growth factor is $1+\frac{5.125}{100}=1 + 0.05125=1.05125$ The new mean is $35240\times1.05125$ $35240\times1.05125=35240\times\left(1+\frac{5.125}{100}\right)=35240+35240\times\frac{5.125}{100}$ $35240\times\frac{5.125}{100}=\frac{35240\times5.125}{100}=\frac{35240\times\frac{5125}{1000}}{100}=\frac{35240\times5125}{100000}$ $35240\times5125=(35000 + 240)\times5125=35000\times5125+240\times5125$ $35000\times5125 = 35000\times(5000+125)=35000\times5000+35000\times125=175000000+4375000 = 179375000$ $240\times5125=240\times(5000 + 125)=240\times5000+240\times125=1200000+30000 = 1230000$ $35240\times5125=179375000+1230000=180605000$ $\frac{35240\times5125}{100000}=1806.05$ $35240+1806.05 = 37046.05$
Answer:
$37,046.05$