there are 100 freshman students at a school. the probability that a freshman plays a sport is 0.55. the…

there are 100 freshman students at a school. the probability that a freshman plays a sport is 0.55. the probability that a freshman plays a musical instrument is 0.34. the probability that a freshman plays both a sport and a musical instrument is 0.15. what is the probability that a freshman student at this school plays either a sport or a musical instrument?\na. 0.23\nb. 0.74\nc. 0.85\nd. 0.89\ne. 1.04

there are 100 freshman students at a school. the probability that a freshman plays a sport is 0.55. the probability that a freshman plays a musical instrument is 0.34. the probability that a freshman plays both a sport and a musical instrument is 0.15. what is the probability that a freshman student at this school plays either a sport or a musical instrument?\na. 0.23\nb. 0.74\nc. 0.85\nd. 0.89\ne. 1.04

Answer

Explanation:

Step1: Recall the formula

Use the formula $P(A\cup B)=P(A)+P(B)-P(A\cap B)$, where $A$ is the event of playing a sport and $B$ is the event of playing a musical instrument.

Step2: Substitute the values

Given $P(A) = 0.55$, $P(B)=0.34$, and $P(A\cap B)=0.15$. Then $P(A\cup B)=0.55 + 0.34- 0.15$.

Step3: Calculate the result

$0.55+0.34 - 0.15=0.74$.

Answer:

B. 0.74