there are 100 letter tiles in the game scrabble. the amount of tiles for each letter is shown.\na - 9 b - 2…

there are 100 letter tiles in the game scrabble. the amount of tiles for each letter is shown.\na - 9 b - 2 c - 2 d - 4\ne - 12 f - 2 g - 3 h - 2\ni - 9 j - 1 k - 1 l - 4\nm - 2 n - 6 o - 8 p - 2\nq - 1 r - 6 s - 4 t - 6\nu - 4 v - 2 w - 2 x - 1\ny - 2 z - 1 blank tiles - 2\nselect all of the statements that are true about the probability of choosing different letters when you pick one tile out of the bag.\n□ it is more likely that a will be chosen over u.\n□ there is a 42% chance that you will pick a vowel.\n□ it is less likely that youll pick a blank tile over a z.\n□ the probability of choosing an m or an n is 8 out of 10.\n□ the tile with the highest probability of being chosen is e.\n□ picking a q is equally likely as picking an x.

there are 100 letter tiles in the game scrabble. the amount of tiles for each letter is shown.\na - 9 b - 2 c - 2 d - 4\ne - 12 f - 2 g - 3 h - 2\ni - 9 j - 1 k - 1 l - 4\nm - 2 n - 6 o - 8 p - 2\nq - 1 r - 6 s - 4 t - 6\nu - 4 v - 2 w - 2 x - 1\ny - 2 z - 1 blank tiles - 2\nselect all of the statements that are true about the probability of choosing different letters when you pick one tile out of the bag.\n□ it is more likely that a will be chosen over u.\n□ there is a 42% chance that you will pick a vowel.\n□ it is less likely that youll pick a blank tile over a z.\n□ the probability of choosing an m or an n is 8 out of 10.\n□ the tile with the highest probability of being chosen is e.\n□ picking a q is equally likely as picking an x.

Answer

Explanation:

Step1: Calculate probability formula

Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$, total number of tiles = 100.

Step2: Probability of picking A

Number of A - tiles = 9, so $P(A)=\frac{9}{100}=0.09$. Number of U - tiles = 4, so $P(U)=\frac{4}{100} = 0.04$. Since $0.09>0.04$, it is more likely that A will be chosen over U.

Step3: Probability of picking a vowel

Vowels are A, E, I, O, U. Number of A = 9, E = 12, I = 9, O = 8, U = 4. Total number of vowels = $9 + 12+9 + 8+4=42$. So $P(\text{vowel})=\frac{42}{100}=42%$.

Step4: Probability of picking a blank tile and Z

Number of blank tiles = 2, so $P(\text{blank})=\frac{2}{100}=0.02$. Number of Z - tiles = 1, so $P(Z)=\frac{1}{100}=0.01$. Since $0.02>0.01$, it is more likely to pick a blank tile over a Z.

Step5: Probability of picking M or N

Number of M - tiles = 2, number of N - tiles = 6. Total number of M or N tiles = $2 + 6=8$. So $P(M\text{ or }N)=\frac{8}{100}=\frac{8}{10}$ is false.

Step6: Identify the tile with highest probability

E has 12 tiles. Comparing with other letters, since 12 is the highest number of tiles among single - letter types, the tile with the highest probability of being chosen is E.

Step7: Probability of picking Q and X

Number of Q - tiles = 1, so $P(Q)=\frac{1}{100}$. Number of X - tiles = 1, so $P(X)=\frac{1}{100}$. So picking a Q is equally likely as picking an X.

Answer:

It is more likely that A will be chosen over U. There is a 42% chance that you will pick a vowel. The tile with the highest probability of being chosen is E. Picking a Q is equally likely as picking an X.