7. a 12 - sided solid has faces numbered 1 through 12.\na. find the probability of rolling a number greater…

7. a 12 - sided solid has faces numbered 1 through 12.\na. find the probability of rolling a number greater than 5.\nb. if the 12 - sided solid is rolled 180 times, how many times would you expect either a 3, 9, or 11 to be rolled?
Answer
Explanation:
Step1: Calculate favorable outcomes for part a
The numbers greater than 5 on a 1 - 12 numbered solid are 6, 7, 8, 9, 10, 11, 12. So there are 7 favorable outcomes. The total number of outcomes is 12.
Step2: Calculate probability for part a
The probability formula is $P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P(\text{number}> 5)=\frac{7}{12}$.
Step3: Calculate favorable outcomes for part b
The numbers 3, 9, 11 are the favorable outcomes. So there are 3 favorable outcomes out of 12 total outcomes.
Step4: Calculate expected value for part b
The expected - value formula is $E = n\times P(A)$, where $n$ is the number of trials and $P(A)$ is the probability of the event. The probability $P(\text{3, 9 or 11})=\frac{3}{12}=\frac{1}{4}$, and $n = 180$. Then $E=180\times\frac{1}{4}=45$.
Answer:
a. $\frac{7}{12}$ b. 45