18 36 23 17 13\nsend data to excel\nthe sample variance for the height increase is \nthe sample standard…

Explanation:

Step1: Calculate the mean

Let the data set be (x = {18,36,23,17,13}). The number of data - points (n = 5). The mean (\bar{x}=\frac{18 + 36+23+17+13}{5}=\frac{107}{5}=21.4)

Step2: Calculate the squared differences

((18 - 21.4)^2=(- 3.4)^2 = 11.56), ((36 - 21.4)^2=(14.6)^2 = 213.16), ((23 - 21.4)^2=(1.6)^2 = 2.56), ((17 - 21.4)^2=(-4.4)^2 = 19.36), ((13 - 21.4)^2=(-8.4)^2 = 70.56)

Step3: Calculate the sample variance

The formula for the sample variance (s^{2}=\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}). (\sum_{i=1}^{5}(x_{i}-\bar{x})^{2}=11.56 + 213.16+2.56+19.36+70.56=317.2). Then (s^{2}=\frac{317.2}{4}=79.3)

Step4: Calculate the sample standard deviation

The sample standard deviation (s=\sqrt{s^{2}}), so (s=\sqrt{79.3}\approx8.905)

Answer:

The sample variance for the height increase is (79.3). The sample standard deviation for the height increase is approximately (8.905).