1st grade\n2nd grade\n3rd grade\n4th grade\nzero\nadd the first four grades then divide by four to calculate…

1st grade\n2nd grade\n3rd grade\n4th grade\nzero\nadd the first four grades then divide by four to calculate the grade average without a zero.\nadd all five grades then divide by five to calculate the grade average with a zero.\nchange the \0\ to a \50\ then add all five grades and divide by five to calculate the grade average with a 50 instead of a zero.\nwhat effect did one \zero\ have on the average grades? how much did the letter grade change? (e.g., from an \a\ to a \c.\)\nsome teachers will let you turn in a late assignment for at least partial credit. how much did changing a \0\ with a partial credit of \50\ change the average grades?

1st grade\n2nd grade\n3rd grade\n4th grade\nzero\nadd the first four grades then divide by four to calculate the grade average without a zero.\nadd all five grades then divide by five to calculate the grade average with a zero.\nchange the \0\ to a \50\ then add all five grades and divide by five to calculate the grade average with a 50 instead of a zero.\nwhat effect did one \zero\ have on the average grades? how much did the letter grade change? (e.g., from an \a\ to a \c.\)\nsome teachers will let you turn in a late assignment for at least partial credit. how much did changing a \0\ with a partial credit of \50\ change the average grades?

Answer

Explanation:

Step1: Calculate average with zero

Let the first four grades be (a = 96), (b = 84), (c = 88), (d = 92) and the fifth - grade (e = 0). The sum of the five grades (S_1=a + b + c + d+e=96 + 84+88 + 92+0=360). The average (A_1=\frac{S_1}{5}=\frac{360}{5}=72).

Step2: Calculate average with 50

Replace (e = 0) with (e = 50). The sum of the five grades (S_2=a + b + c + d+e=96 + 84+88 + 92+50=410). The average (A_2=\frac{S_2}{5}=\frac{410}{5}=82).

Step3: Find the difference in averages

The difference (\Delta A=A_2 - A_1=82 - 72 = 10).

Answer:

The average grade increased by 10 when the grade was changed from 0 to 50.